Interference fringes on the screen and the intensity I = 4I₀ cos²(πxd/λD)पर्दे पर व्यतिकरण फ्रिंज और तीव्रता I = 4I₀ cos²(πxd/λD)Interference fringes on the screen and the intensity I = 4I₀ cos²(πxd/λD)
NCERT Fig 10.13 · Class 12 Physics · Chapter 10 · interactive diagram
Read Chapter 10 with this diagramइस डायग्राम के साथ अध्याय 10 पढ़ेंIs diagram ke saath Ch 10 padhiyeAll Physics diagramsसभी भौतिकी डायग्रामSaare Physics diagrams
Parts and what they mean
- Fringes (bright and dark bands) (फ्रिंज (दीप्त और अदीप्त पट्टियाँ)) — Equally spaced bright and dark bands (computed from the formula).
- Central bright fringe (केंद्रीय दीप्त फ्रिंज) — At x = 0 the path difference is zero.
- First bright fringe (पहला दीप्त फ्रिंज) — Bright fringes at xₙ = nλD/d (n = 0, ±1, ±2, …).
- Dark fringe (अदीप्त फ्रिंज) — Dark fringes at xₙ = (n + ½)λD/d: here I = 0.
- Fringe width β (फ्रिंज चौड़ाई β) — β = xₙ₊₁ − xₙ = λD/d — the same for bright and dark fringes. Bigger λ or D, or smaller d → wider fringes.
- Intensity curve (तीव्रता वक्र) — I = 4I₀ cos²(φ/2) with φ = 2πxd/(λD). Maxima 4I₀, minima 0; the average is 2I₀ — energy is only redistributed.
Original diagram drawn by Simple Learning Hub, based on NCERT Fig 10.13. Report a mistake